If f(x)+f(1/1-x)=2(1-2x)/x(1-x) then f(x)=
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This is pretty simple. Using basics of remainder theorem, remainder of f(x) when divided with (x-a) will be f(a).
So from the above data, f(-1) = 6 and f(1) = 0.
Substituting it, 3(-1)^4-a(-1)^3+2a(-1)^2-(-1)-b = 6
i.e. 3+a+2a+1-b = 6 => 3a - b = 2
Also 3(1)^4-a(1)^3+2a(1)^2-(1)-b = 0
i.e. 3-a+2a-1-b = 0 => a - b = -2
Solving these two equations, we can get a = 2, b = 4.
So from the above data, f(-1) = 6 and f(1) = 0.
Substituting it, 3(-1)^4-a(-1)^3+2a(-1)^2-(-1)-b = 6
i.e. 3+a+2a+1-b = 6 => 3a - b = 2
Also 3(1)^4-a(1)^3+2a(1)^2-(1)-b = 0
i.e. 3-a+2a-1-b = 0 => a - b = -2
Solving these two equations, we can get a = 2, b = 4.
avanirook:
Again done it for point
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