If f (x) is a linear function such that f (-4)=1 and f (5)=7,2hat is the value of f (1250)?
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a/c to question, f(x) is a linear function.
Suppose f(x) = ax + b , where a and b are constant
given, f(-4) = 1
f(-4) = a(-4) + b = 1
-4a + b = 1 ......(1)
again, f(5) = 7
f(5) = 5a + b = 7 ........(2)
solve equations (1) and (2),
9a = 6 => a = 2/3 and b = 7 - 5 × 2/3 = 7 - 10/3 = 11/3
hence, f(x) = 2x/3 + 11/3
now, f(1250) = 2 × 1250/3 + 11/3
f(1250) = (2500 + 11)/3 = 2511/3 = 837
hence, f(1250) = 837
Suppose f(x) = ax + b , where a and b are constant
given, f(-4) = 1
f(-4) = a(-4) + b = 1
-4a + b = 1 ......(1)
again, f(5) = 7
f(5) = 5a + b = 7 ........(2)
solve equations (1) and (2),
9a = 6 => a = 2/3 and b = 7 - 5 × 2/3 = 7 - 10/3 = 11/3
hence, f(x) = 2x/3 + 11/3
now, f(1250) = 2 × 1250/3 + 11/3
f(1250) = (2500 + 11)/3 = 2511/3 = 837
hence, f(1250) = 837
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