if f(x) is a quadratic polynomial with f(2)=10&f(-2)=-2 then coefficient of x in f(x) is
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Hey there!
Praneeth from Brainly.in here to help!
Let f(x) =ax²+bx+c=0
here
➤ a is the x² coefficient
➤ b is the x- coefficient
➤ c is the constant
To get f(2) substitute the value of 2 in place of x
➫f(2)=a(2)²+b(2)+c=10
➫ f(2)=4a+2b+c=10
To get f(-2) substitute the value of -2 in place of x
➫f(-2)=a(-2)²+b(-2)+c=-2
➫ f(-2)=4a-2b+c=-2
Subtracting f(-2) from f(2)
➫ 4a+2b+c-4a+2b-c =10-(-2)
➫( 4a-4a)+(2b+2b)+(c-c)=12
➫ 0+4b+0=12
➫ 4b=12
➫b =3
Therefore x coefficient is 3
hope helped!!
Praneeth from Brainly.in here to help!
Let f(x) =ax²+bx+c=0
here
➤ a is the x² coefficient
➤ b is the x- coefficient
➤ c is the constant
To get f(2) substitute the value of 2 in place of x
➫f(2)=a(2)²+b(2)+c=10
➫ f(2)=4a+2b+c=10
To get f(-2) substitute the value of -2 in place of x
➫f(-2)=a(-2)²+b(-2)+c=-2
➫ f(-2)=4a-2b+c=-2
Subtracting f(-2) from f(2)
➫ 4a+2b+c-4a+2b-c =10-(-2)
➫( 4a-4a)+(2b+2b)+(c-c)=12
➫ 0+4b+0=12
➫ 4b=12
➫b =3
Therefore x coefficient is 3
hope helped!!
dhruvchoubey:
thanks
Answered by
1
Step-by-step explanation:
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