If f(x) is an odd periodic function with period 2, then f(4)
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2
ANSWER
Since f(x) is an odd periodic function with period 2
∴f(x)=−f(x) and f(x+2)=f(x)
∴f(2)=f(0+2)=f(0)
and f(−2)=f(−2+2)=f(0)
Now f(0)=f(−2)=−f(2)=−f(0)
∴f(4)=f(2+2)=f(2)=f(0)=0
Or
ANSWER
Given f(x) is an odd period function period function
→f(−x)=−f(x) and f(0)=0
since f(x) has period 2.
∴f(0)=f(2)=f(4)=0
Hence f(4)=0
Hope it helps you
Since f(x) is an odd periodic function with period 2
∴f(x)=−f(x) and f(x+2)=f(x)
∴f(2)=f(0+2)=f(0)
and f(−2)=f(−2+2)=f(0)
Now f(0)=f(−2)=−f(2)=−f(0)
∴f(4)=f(2+2)=f(2)=f(0)=0
Or
ANSWER
Given f(x) is an odd period function period function
→f(−x)=−f(x) and f(0)=0
since f(x) has period 2.
∴f(0)=f(2)=f(4)=0
Hence f(4)=0
Hope it helps you
Answered by
5
Solution:- Given that f(x) is an odd function .
i.e f(-x) = -f(x)
Put x = 0
- ⟹F(0) = - f (0)
- ⟹ 2f(0) = 0
- ⟹ f(0) = 0
Also given function with period 2
∵ f(0) = 0
∴f(0) = f(0+2) =f(0+4) = f(0+6) ....... = 0
Since, f(4) = 0 Answer
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