If f(x) is divided by x – 3 then the remainder is 5, and when it is divided by (x - 4) the
remainder is 'O'. Then the remainder when it is divided by (x - 3)(x - 4) is
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9th
Maths
Polynomials
Remainder Theorem
Let P(x) be a polynomial, w...
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Let P(x) be a polynomial, which when divided by x−3 and x−5 leaves remainders 10 and 6 respectively. If the polynomial is divided by (x−3)(x−5) then the remainder is :
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P(x) when divided by x−3 and x−5 leaves remainder 10 and 6 respectively.
From polynomial-remainder theorem, P(3)=10 and P(5)=6
If the polynomial is divided by (x−3)(x−5) then remainder must be of the form ax+b (degree of remainder is less than that of divisor)
⇒P(x)=Q(x)(x−3)(x−5)+(ax+b), where Q(x) is some polynomial.
Substituting for x=3 and x=5:
P(3)=10=3a+b
P(5)=6=5a+b
Solving for a and b, we get
a=−2 and b=16
⇒Remainder=−2x+16
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ans=
remainder therom =
-5x+20
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