If f(x) is divided by (x − 97) then remainder is
(a) 0 (b) 97 (c) 1 (d) f(97)
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Answer:
Here, p(x)=x
100
−x
97
+x
3
, and the zero of x+1 is −1
So, p(−1)=(−1)
100
−(−1)
97
+(−1)
3
=1+1−1
=1
So, by the Remainder Theorem 1 is the remainder when x
100
−x
97
+x
3
is divided by x+1.
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