If f(x) is odd and differentiable, then f'(x) is= ?
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Answer:
If f(x) is odd and differentiable, then f′(x) is an even function.
Step-by-step explanation:
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Step-by-step explanation:
I've seen some proofs but I don't really get it..I find it hard to understand..
I've done this so far:
f′(x)===limh→0f(x)−f(x+h)h (since f(x) is odd f(−x)=−f(x))limh→0−f(−x)+f(−x−h)hlimh−→0f(−x−h)−f(−x)h
But I don't know how to go from here and make it equal to f′(−x).
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