If f(x) is the p.d.f of the continuous random variable x, then E(x²) is
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Hi ,
If f( x ) is the probability density
function ( PDF ) of a continuous
random variable x , then
*****************************************
E( X² ) = integral of ( - infinity to + infinity ) x²f( x ) dx
******************************************
Therefore ,
Option ( c ) is correct.
I hope this helps you.
: )
If f( x ) is the probability density
function ( PDF ) of a continuous
random variable x , then
*****************************************
E( X² ) = integral of ( - infinity to + infinity ) x²f( x ) dx
******************************************
Therefore ,
Option ( c ) is correct.
I hope this helps you.
: )
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