If f(x)=ln
(1- 1/x^2). The value of f(2)+F(3)+f(4) is:
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f(x) = (1- 1/x^2)
f(2) = (1 - 1/2^2) = (1 - 1/4) = 3/4
f(3) = (1- 1/3^2) = (1- 1/9) = 8/9
f(4) = (1- 1/4^2) = (1- 1/16) = 15/16
f(2)+F(3)+f(4) = 3/4 + 8/9 + 15/16
= (3*9*16 + 8*4*16 + 15*4*9)/(4*9*16)
= (432 + 512 + 540)/(576)
=1484/576
=2.576
hope it helps!!!
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