Question

if f(x)=log (1+x÷1-x), then f (2a÷1+a sqaure)

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Answer 1

Answer:

=2(log(1+a) - log(1-a))

Step-by-step explanation:

f(x) is log(1+x/1-x)

we have to find f(2a/1+a²)

if this is what you are asking

then

f(2a/1+a²)is equal to log(1+2a/1+a² ÷ 1-2a/1+a²

==> f(2a/1+a²) = log (1 + a² + 2a/1 + a² ÷ 1 + a² -2a/1 + a²)

=log (1+a²+2a/1+a²-2a)

=log((1+a)²/(1-a)²)

=log(1+a/1-a)²

=2log(1+a/1-a)

=2(log(1+a) - log(1-a))