Math, asked by starmogh5081, 10 months ago

If f (x) = one-ninth x minus 2, what is mc003-2.jpg?

Answers

Answered by AditiHegde
41

The complete question is,

If f(x)=1/9x-2, what is f^–1(x)?

A.) f^–1(x) = 9x + 18

B.) f^-1(x)=1/9x+2

C.) f^–1(x) = 9x + 2

D.) f^-1(x)=-2x+1/9

Given,

f(x) = 1/9 x - 2

To find: f^-1(x)  ⇒ inverse of f(x)

We are given with,

f(x) = 1/9 x - 2

f(x) + 2 = 1/9 x

9 [ f(x) + 2 ] = x

Now let us consider the inverse of the function,

f ^-1(x) = { 9 [ f(x) + 2 ]  } ^-1

f ^-1(x) = 9 (x+2)

f ^-1(x) = 9x + 18

Therefore option A is correct.

Answered by amitnrw
8

Given : f(x)  = (1/9)x  -  2

To find  : Inverse function of f(x)

Solution:

f(x) = (1/9)x  -  2

=> f(x) + 2 = (1/9)x

=> x = 9 ( f(x) + 2)

Lets replace value of x & f(x)  to find inverse function

=> f⁻¹(x) = 9(x + 2)

=> f⁻¹(x)  = 9x + 18

f⁻¹(x) = 9x + 18

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