If f(x) = {sin2x/tan 3x'
=
(k,
X=0
x #0
is continuous at x = 0, then value of k is:
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Answer:
cos 2^-3
Step-by-step explanation:
= f(x) = sin2x/tan3x
= f(x) = sin2/tan3
= f(x) = cos2^-3
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