Question

if f(x)=(x+1) squared and g(x)= 2[f(x)]-4, what is the sum of all values of x for which f(x)=g(x)?

Answer 1

Answer:

x^2-3+2x

Step-by-step explanation:

f(x)=(x+1)^2

and g(x)=2[f(x)]-4

then substituting f(x) in g(x) as f(x)=g(x)

then

g(x)=2(x+1)^2-4. [ (a+b)^2=a^2+b^2+2ab]

that means

2[x^2+1^2+2( x)(1)]-4

2(x^2+1+2x)-4= ( x+1)^2

2x^2+2+4x-4=x^2+1+2x

reciprocal

-4=x^2+1+2x-2x^2-2-4x

-4=-x^2-1-2x [ again reciprocal ]

x^2+1+2x-4=0

x^2-3+2x (is the value of x)