If f(x) = x-1/x+1 is invertible function
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y = (x-1)/(x+1)
=> xy+y = x-1
=> xy - x + y+1 = 0
=> x(y-1) = -(y+1)
=> x = (y+1)/(1-y)
=> f^-(x) = (x+1)/(1-x)
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