Question

If f(x)=x+1/x-1, then find f(f(f(2)))

Answer 1

Answer:

Step-by-step explanation:

f(x) =(x+1/x-1)

f(f(x)) = [(x+1/x-1) + 1] / [(x+1/x-1) - 1]

f(f(f(x))) = {[(x+1/x-1) + 1] / [(x+1/x-1) - 1] + 1} / {[(x+1/x-1) + 1] / [(x+1/x-1) - 1] - 1}

f(f(f(2))) =  {[(2+1/2-1) + 1] / [(2+1/2-1) - 1] + 1} / {[(2+1/2-1) + 1] / [(2+1/2-1) - 1] - 1}

           = [(3 + 1)/(3 - 1) + 1]/[(3 + 1)/(3 - 1) - 1]

           = [(4/2) + 1]/[(4/2) - 1]

           = (2 + 1)/ (2 - 1)

           = 3/1

            = 3