if f(x)= x-1/x+1,x is not equal to 1, show that f(f(x))=-1/x,where x is not equal to 0
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Solution:
if f(x)= x-1/x+1,x is not equal to 1, show that f(f(x))=-1/x,where x is not equal to 0.
f(x) = (x-1)/(x+1)
LHS = f[f(x)]
= f[(x-1)/(x+1)]
= [(x-1)/(x+1)-1]/[(x-1)(x+1)+1]
= [(x-1)-(x+1)]/[(x-1)+(x+1)]
= (x-1-x-1)/(x-1+x+1)
= (-2)/(2x)
= -1/x
= RHS
Hence , prooved.
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0
Answer:
the correct answer is -1/x
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