if f(x) = x+1/ x-2, g(x) = 1+2x/ x-1 then fog (x) is
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f(x) = x+1/ x-2, g(x) = 1+2x/ x-1
fog (x) = f ( g ( x )
= f ( 1+2x/ x-1 )
= {( 1+2x/ x-1 ) + 1 } / { (1+2x/ x-1 ) - 2 }
= {(1 + 2x + x -1 )/ (x-1) } / {(1 + 2x - 2(x -1 ) ) / (x-1) }
= 3x / (1 + 2x - 2x + 2)
= 3x / 3
= x ( answer )
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