Question

if f(x)=x÷1-x and g(x)=x-1÷x then gof

Answer 1

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$f(x) = \frac{x}{1-x}$

$g(x) = \frac{1-x}{x}$

$gof = g[f(x)]$

$g[f(x)] = \frac{\frac{x}{1-x}-1 }{\frac{x}{1-x} } \\= \frac{\frac{x-1+x}{1-x} }{\frac{x}{1-x} }$

$= \frac{2x-1}{x}$

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