if f(x)= x-1/x prove that [f(x)]^3=f(x)^3 -3f(1/x)
Answers
Answered by
24
First of all the question should be,
Prove that
f(x³)=[f(x)]³-3f(1/x)
So,
First considering Right hand side,
=[f(x)]³-3f(1/x)
=(x- 1/x )³ -3 (1/x - x)
=(x³ - (1/x)³) - 3(x × (1/x) (x- 1/x)) -3 (1/x - x)
=(x³ - (1/x)³) -3 (x- 1/x) +3 ( x - 1/x)
=x³ - (1/x)³
Now, considering Left hand side.
f(x³)=x³ - (1/x)³
So,
We conclude that LHS= RHS
Hence proved
Prove that
f(x³)=[f(x)]³-3f(1/x)
So,
First considering Right hand side,
=[f(x)]³-3f(1/x)
=(x- 1/x )³ -3 (1/x - x)
=(x³ - (1/x)³) - 3(x × (1/x) (x- 1/x)) -3 (1/x - x)
=(x³ - (1/x)³) -3 (x- 1/x) +3 ( x - 1/x)
=x³ - (1/x)³
Now, considering Left hand side.
f(x³)=x³ - (1/x)³
So,
We conclude that LHS= RHS
Hence proved
Answered by
35
In the attachments I have answered this problem.
I have applied the following algebraic identity to get the required result.
(a-b)^3 = a^3 - b^3 - 3ab(a-b)
The above identity is modified and suitable simplifications are made to get the final answer.
I hope this answer helps you
I have applied the following algebraic identity to get the required result.
(a-b)^3 = a^3 - b^3 - 3ab(a-b)
The above identity is modified and suitable simplifications are made to get the final answer.
I hope this answer helps you
Attachments:
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