Question

If f(x)=x^2\1-x^2 then prove that f(sin)= tan^2​

Answer 1

Answer:

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Step-by-step explanation:

ur answer is there in image

Answer 2

Answer:

f(x)=x^2\1-x^2

then

$f(sinx) = \frac{ {sin}^{2}x }{1 - {sin}^{2} x} \\ = \frac{ {sin}^{2} x}{ {cos}^{2} x} = {tan}^{2} x$