if f(x)=(x^2+2x+3)/x^2-8x+12 find value of x if f(x)=1
Answers
Answered by
6
Answer:
Step-by-step explanation:
Hello!
f(x) = x² + 2x + 1 / x² - 8x + 12
= (x + 1)² / x² - 2x - 6x + 12
= (x + 1)² / x.(x - 2) - 6.(x - 2)
= (x + 1)² / (x - 2).(x - 6)
In real numbers, denominator can't be zero.
Then,
(x - 2).(x - 6) ≠ 0
∴ x ≠ 2 and x ≠ 6
Hence, the domain = R - {2,6}
Cheers!
Similar questions