Question

if f(x)=(x^2+2x+3)/x^2-8x+12 find value of x if f(x)=1​

Answer 1

Answer:

Step-by-step explanation:

Hello!

f(x) = x² + 2x + 1 / x² - 8x + 12

= (x + 1)² / x² - 2x - 6x + 12

= (x + 1)² / x.(x - 2) - 6.(x - 2)

= (x + 1)² / (x - 2).(x - 6)

In real numbers, denominator can't be zero.

Then,

(x - 2).(x - 6) ≠ 0

∴ x ≠ 2 and x ≠ 6

Hence, the domain = R - {2,6}

Cheers!