Math, asked by tanmayjondhale729, 8 months ago

If f(x) = x^2 – 3x + 1 , find f(0) & f(-3)

Answers

Answered by Anonymous

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$\large {\tt {Answer:}}$

${\tt {f(x) = {x}^{2} - 3x + 1}}$

${\tt {f(0) = {0}^{2} - 3(0) + 1}}$

${\tt {f(0) = 0 - 0 + 1}}$

${\tt {f(0) = 1}}$

${\tt {f( - 3) = { - 3}^{2} - 3( - 3) + 1}}$

${\tt {f( - 3) = 9 - 27 + 1}}$

${\tt {f( - 3) = 9 - 26}}$

${\tt {f( - 3) = - 17}}$

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Answered by aleenaaringada

Step-by-step explanation:

x)=x2−3x+1

{\tt {f(0) = {0}^{2} - 3(0) + 1}}f(0)=02−3(0)+1

{\tt {f(0) = 0 - 0 + 1}}f(0)=0−0+1

{\tt {f(0) = 1}}f(0)=1

{\tt {f( - 3) = { - 3}^{2} - 3( - 3) + 1}}f(−3)=−32−3(−3)+1

{\tt {f( - 3) = 9 - 27 + 1}}f(−3)=9−27+1

{\tt {f( - 3) = 9 - 26}}f(−3)=9−26

{\tt {f( - 3) = - 17}}f(−3)=−17

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