if f (x) = x + 2 ÷ 3x - 1 then find f(f (x))
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1
Answer:
f(x)=x
2
−3x+1
f(2α)=(2α)
2
−3(2α)+1=4α
2
−6α+1
f(2α)=2f(α)
∴4α
2
−6α+1=2(α
2
−3α+1)
4α
2
−6α+1=2α
2
−bα+2
4α
2
+1=2α
2
+2
2α
2
=1 α=±
2
1
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