if f(x)=x^2+3x+2 find the value of x for which f(x+1)=f(x)
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Hii its tom85
f(x)=x^2+3x+2
f(x+1)= x^2 + 2x +1 + 3x+ 3 +2
f(x+1)= x^2 + 5x + 6
given
f(x) = f(x+1)
x^2 + 3x + 2 = x^2 + 5x + 6
-2x = 4
x= -2
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hope it may helps you
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