Question

if f(x)=x^2-4x+8 then the range of f is​

Answer 1

$f(x) = {x}^{2} - 4x + 8 \\ = {x}^{2} - 4x + 4 + 4 \\ = ({x - 2})^{2} + 4$

Here,

$( {x - 2})^{2}$

Is either non -ve number i.e greater than Eq to zero

$f(x) \geqslant 0 + 4 \\ f(x) \geqslant 4$

RANGE

$4 \leqslant f(x) > \infty$

PLEASE MARK AS BRAINLIEST

Answer 2

Answer:

bro I think this is the correct answer

Step-by-step explanation:

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and bro I am from banglore where r u from