If f(x)=x^2-5x+7then evaluate f(2)-f(-1)+f(1/3)
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f(2)=(2^2)-5(2)+7
=4-10+7
=1
f(-1)=(-1^2)-5(-1)+7
=1+5+7
=13
f(1/3)=(1/3)^2-5(1/3)+7
=1/9-5/3+7
=49/9
1-13+49/9
=-59/9
=4-10+7
=1
f(-1)=(-1^2)-5(-1)+7
=1+5+7
=13
f(1/3)=(1/3)^2-5(1/3)+7
=1/9-5/3+7
=49/9
1-13+49/9
=-59/9
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