if f(x)=x^2 sin 1/x when x is not = 0 =0, when x=0 Then find the derivative of f(x) at x=0
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Answer:
Lim f (×)= x tends to 0 , but -1 is less than or equal to sin ( 1/x ) greater than to -1 and x tends to zero then
lim f (x) = 0 x tends to zero =0=f (0).
Therefore f (x) is continuous at x=0
Also the function f (x) =x square sin (1/x) is
differentiable because
Rf(x) =lim h tends to zero h square sin 1/h-0/h=0
Lf (x) = lim h tends to zero h square sin (1/-h)/-h =0
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