If f(x) =x^3-1/x^3, show that f(x) +f1/x=0
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Here we have a function,
F(x)=x³−1/x³−−−−(1)
If we put x=1/x
We get,
F(1/x)=(1/x)³−(x)³--------(2)
Adding equation 1 & 2
We get,
F(x)+F(1/x)=x³-1/x³+1/x³−x³=0
F(x)=x³−1/x³−−−−(1)
If we put x=1/x
We get,
F(1/x)=(1/x)³−(x)³--------(2)
Adding equation 1 & 2
We get,
F(x)+F(1/x)=x³-1/x³+1/x³−x³=0
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