Question

If f (x)= x^3+1/x^3 Then amount of f (x) -f (1/x) is equal to ​

Answer 1

Answer:

0

Step-by-step explanation:

f (x)= x^3+1/x^3

f (1/x)= ((1/x)^3)+(x^3)

        = x^3+1/x^3

so f(x) = f(1/x)

f(x)-f(1/x)=0

Answer 2

Answer:

0

Step-by-step explanation:

$f(x) = {x}^{3} + \frac{1}{ {x}^{3} } \\ f(x - 1) = \frac{1}{{x}^{3} + \frac{1}{ {x}^{3} }} \\ f(x) -f(x - 1) = {x}^{3} + \frac{1}{ {x}^{3} } - \frac{1}{{x}^{3} + \frac{1}{ {x}^{3} }} \\ = {x}^{3} + \frac{1}{ {x}^{3} } - \frac{1}{ {x}^{2} } - {x}^{3} \\ = 0$