Math, asked by khandareshubh15, 2 months ago

IF f (x)=x^3-2x+ 10 then f'(2)=?​

Answers

Answered by dharamvam
1

Answer:

your answer:

f(2)=14

Explanation:

f(x)=x³-2x+10

f(2)=?

put x=2 in the above equation

f(2)=(2)³-2(2)+10

f(2)=8-4+10

f(2)=4+10

f(2)=14

Answered by Flaunt
18

Given

we have given f(x) = x³-2x+10

To find

we have to find f'(2)

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Note : Any change in f(x) will cause a change in the function.

Now ,our function is f(x) and we have to find f(2) now compare the coefficient of f(x) with f(2) , we find x=2

So,we have to find the value of f(x) at x=2

at x= 2

=>f(x)= x³-2x+10

=>f(2)= (2)³-2(2)+10

=>f(2)=8-4+10

=>f(2)= 4+10

=>f(2)=14

Therefore ,f(2) is 14

Extra information=>

➥The above function is cubic polynomial equation as highest power is 3.

➥f(x)=y here ,f is the function and x is an input which gives output say 'y'.

➥We can find infinite number of output of f(x) by putting infinite number of values into f(x).

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