If f(x) = (x^3) - 3*(x^2)+ (x) and g is the inverse of f , then g'(3) is
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here is your answer mate...
Step-by-step explanation:
f(x) = (x^3) - 3*(x^2)+ (x)
g(3)= -((x^3) - 3*(x^2)+ (x))
g(3)= -(27-27+3)
g(3)= -3
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