Question

if f(x) =X^3+3x^2-2x+4 find the value of f(-2)+f(2)-f(0)​

Answer 1

Answer:28

Step-by-step explanation:f(x)=x³+3x²-2x+4

f(2)=2³+3(2)²-2(2)+4

=8+12-4+4

=20

f(-2)=(-2)³+3(-2)²-2(-2)+4

= -8+12+4+4

=12

f(0)=0³+3(0)²-2(0)+4

= 4

We need to find f(-2)+f(2)-f(0)

=12+20-4

=28