Math, asked by jyothinaidu9408, 11 months ago

If f(x)=x^3-3x^2+3x-1 and f'(a) = 0,find value of a.

Answers

Answered by Anonymous
5

Answer:

f(x)=x³-3x²+3x-1

f(0)=0³-3×0²+3×0-1=0

-1=0

Answered by Robrozz
0

Answer:

answer is minus 1

Step-by-step explanation:

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