If f(x)=x^3-3x^2+3x-1 and f'(a) = 0,find value of a.
Answers
Answered by
5
Answer:
f(x)=x³-3x²+3x-1
f(0)=0³-3×0²+3×0-1=0
-1=0
Answered by
0
Answer:
answer is minus 1
Step-by-step explanation:
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