Question

if f(x)x^3-5x^2-4x+20 show that f(0)= -2f(3)​

Answer 1

Answer:

$f(x) = {x}^{3} - 5 {x}^{2} - 4x + 20 \\ f(0) = 0 - 0 - 0 + 20 \\ f(0) = 20 \\ f(3) = {3}^{3} - 5 \times {3}^{2} - 4 \times 3 + 20 \\ f(3) = 27 - 45 - 12 + 20 \\ f(3) = - 10 \\ - 2f(3) = 20$

HENCE LHS = RHS

$f(0) = - 2f(3)$

hope it helps.......