Question

If f (x)= x+3) and (x)=3x²+2 find the value of fog (3) and gof (5)

Answer 1

fog (x) = f(g(x))

Here, fog (x) = (3x² + 2) + 3 = 3x² + 5

So, fog (3) = 27 + 5 = 32

Also, gof (x) = 3(x + 3)² + 2

So, gof (5) = 3 × 64 + 2 = 194

Your question is not clear but I solved. Values may differ, but the procedure is same.

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