Math, asked by sumiyakm8737, 11 months ago

If f (x)=x^3 find the value of f (5)-f (1)/5-1

Answers

Answered by jitendramishra73
9

Answer:

31

Step-by-step explanation:

f(x)=x^3 = f(5)-f(1)/5-1

5^3-1^3/5-1

124/4

31

Answered by gayatrikumari99sl
0

Answer:

124 is the value f(5) - \frac{f(1)}{5}  - 1

Step-by-step explanation:

Explanation:

Given, f(x) = x^3

And we need to find the value of f(5) - (\frac{f(1)}{5} ) - 1

So, we need to first find the value of f(5) and f(1).

Step 1:

From the question, f(x) = x^3

So, f(5) = (5)^3 = 125.

and f\f(1) = (1)^3 = 1.

Now , put the value of  f(5) and  f(1) in f(5) - \frac{f(1)}{5}  - 1 we get,

f(5) - \frac{f(1)}{5}  - 1

f(5) - \frac{f(1)}{5}  - 1 = 125 - \frac{1}{5} -1=  \frac{125 (5)- 1-5}{5} = \frac{625 - 6}{5}

f(5) - \frac{f(1)}{5}  - 1 = \frac{619}{5} = 123.8 = 124.

Final answer:

Hence, the value of f(5) - \frac{f(1)}{5} - 1 is 124.

#SPJ3

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