if f(x)=x^3+x^2-2x+4 then f(-1)+f(0)
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Step-by-step explanation:
f(x)=x³+3x²-2x+4
f(2)=2³+3(2)²-2(2)+4
=8+12-4+4
=20
f(-2)=(-2)³+3(-2)²-2(-2)+4
= -8+12+4+4
=12
f(0)=0³+3(0)²-2(0)+4
= 4
We need to find f(-2)+f(2)-f(0)
=12+20-4
=28
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