If f(x) =x^3 + x^2 -ax +b is divisible by x^2 - x . Find the value of a and b .
Its urgent.....
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Hey dear!
Here is yr answer.....
x²-x = 0
x(x-1) = 0
x and (x-1) are the factors....
Here, 0 and 1 are the zeros of x³+x²-ax+b
f(x) = x³+x²-ax+b
f(0)
0³+0²-a(0)+b = 0
b = 0
f(1)
1³+1²-a(1)+0 = 0
1+1-a = 0
2-a = 0
-a = -2
a = 2
Therefore, a = 2 , b = 0
Hope it hlpz....
Here is yr answer.....
x²-x = 0
x(x-1) = 0
x and (x-1) are the factors....
Here, 0 and 1 are the zeros of x³+x²-ax+b
f(x) = x³+x²-ax+b
f(0)
0³+0²-a(0)+b = 0
b = 0
f(1)
1³+1²-a(1)+0 = 0
1+1-a = 0
2-a = 0
-a = -2
a = 2
Therefore, a = 2 , b = 0
Hope it hlpz....
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