If f(x)=x^3+x^2-ax+b is divisible by x^2-x, then find the values of a and b.
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the value of a=2
and b=o
first of all you have to divide f(x) by x2-x
at last step you will get
2x-ax+b as remainder.
but question said that it is divisible so,
2x-ax+b=0
2x=ax-b
2x-0=ax-b
hence
a=2
b=0
and b=o
first of all you have to divide f(x) by x2-x
at last step you will get
2x-ax+b as remainder.
but question said that it is divisible so,
2x-ax+b=0
2x=ax-b
2x-0=ax-b
hence
a=2
b=0
Irina786:
plz show the complete method
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