If f(x)= x-3/x,g(x)=x+3 , and h(x)=2x+1, what is (g*h*f)(x)
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f(X)= x-3/X
g(X)=X+3
h(X)=2x+1
now
(g*f*h)(X) =
(g*f)h(X) =
(g*f)(2x+1)
(g)f(2x+1)
from 1
put 2x+1in "X"place in f(X)
x-3/X =>2x+1-3/2x+1==>
2x-2/2x+1
i.e
g(2x-2/2x+1)
== X+3 => (2x-2/2x+1) + 3
2x-2+ 6x+3/2x+1
=> 8x+1/2x+1
hope it is helpful to you
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