If f(x)=x^4-2x^3+3x^2-ax+8 is a polynomial such that when it is divided by (x-1) the remainder is 5. Determine the remainder when f(x)is divided by (x+1)
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drrajeevvij:
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Answer:
F(1)=1-2+3-a+8=5
Then a=5
Therefore f(-1)=1+2+3+5+8=19
The reminder when f(x) is divided by x+1 is 19
Thanks sprao
But why us the value of 'a' 5 please tell
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I understood
when f(x) is divided by x-1, the remainder is 5. that is f(1)=5.hence a=5.
Yes thanks a lot
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