Question

If f(x)=x^4-2x^3+3x^2-ax-b when divided by x-1, the remainder is 6.Then find the value of a+b​

Answer 1

f(x) = x^4-2x^3+3x^2-ax-b

g(x) = x-1 = 0

or x= 1

Acc, to remainder theoram

(1)^4 -2(1)^3+3(1)^2-a(1)-b = 6

or

1-2+3-a-b = 6

or

-a-b = 6+2-3-1

or

-a-b = 4

or

a+b = -4

Answer 2

so a+b= 4+(-8)

=4-8

-4 ans