Question

if f(x) = x^4-2x^3+3x^2-mx- n when divided by x-1 ,the remainder is 6 then find the value of m and n if m-n =6​

Answer 1

Answer:

m=4,n=-2

Step-by-step explanation:

(x)^4-2(x)^3+3(x)^2-m(x)-n=0

(x-1=0;x=1) (1)^4-2(1)^3+3(1)^2-m(1)-n=0

1-2+3-m-n=0

-1+3-m-n=0

2-m-n=0

2=m+n

m-n=6 m-n=6, (m=4)

m+n=2 -n=6-4

2m+0n=8 -n=2

m=4 n=-2