Question

if f (x) = x^4+x^2+1/x^2-x-1. then f(w) is (where w is non real root of the equation x^3=1)​

Answer 1

Answer:

0

Step-by-step explanation:

W is non real  and cube root of 1

W^3=1,W^4=W

f(W) =(w^4 +w^2+1)/(w^2-w-1)

       =(w+w^2+1)/(w^2-w-1)  here 1+w+w^2 =0  and -1-w =w^2

       =0/2w^2

       =0