If f(x)=x+7 and g(x)=1/x-13, what is the domain of (f 0 g)(x)?A. {X|X=6},B.{X|X=-6},C.{X|X=-13},D.{X|X=13}
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Answered by
126
Hey There,
There are a few errors in the options.
All the "=" signs should actually be "≠" signs.
Going by that, the answer is Option D, which would be correctly written as
{x|x≠13}
The solution is shown in the image.
Hope it helps,
Purva
Brainly Community
There are a few errors in the options.
All the "=" signs should actually be "≠" signs.
Going by that, the answer is Option D, which would be correctly written as
{x|x≠13}
The solution is shown in the image.
Hope it helps,
Purva
Brainly Community
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Answered by
13
f(x) = x+7
g(x) = 1/(x-13)
fog(x) = [1/(x-13)] + 7
The denominator of the fraction cannot be equal to zero.
So, the domain of fog(x) is x∈R~{13}
g(x) = 1/(x-13)
fog(x) = [1/(x-13)] + 7
The denominator of the fraction cannot be equal to zero.
So, the domain of fog(x) is x∈R~{13}
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