Question

if f(x)=x ka power 2 -3x+1 and f(2a) =2f(a) when a=?
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Answer 1

Answer:

It is simple. Let y = f(x) = (a - x^n)^(1/n) ==> y^n = (a - x^n) . We may write y = f(x)

= exp((1/n)in(a - x^n)) . Therefore f(f(x)) = f(y) ==> f(y) = exp[(1/n) in(a - y^n)]

= exp[(1/n)in(a - a + x^n)] = exp[(1/n)in(x^n)]

= exp[(n/n) in(x)] = exp[ in(x)] = x .