Question

if f(x) = x raise to power 4 - 2x cube + 3x square - ax + 8 when divided by (x-1) is 5 determine the remainder when f(x) is (x-2) and (x+2)
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Answer 1

Answer:

f(x) = x^(4-2x³) + 3x² - ax + 8

Do you mean this.....???? bro

Answer 2

Answer: 10 and 62

Step-by-step explanation:

Given , p(x) = x^4 - 2x^3 + 3x^2 -ax +8

x-1=0 => x=1

p(x) = 1^4 - 2×(1^3) + 3×(1^2) - a×1 + 8

= 1 - 2 + 3 - a + 8

= 10 - a = 5 ( given)

=> a = 10 - 5

a = 5

f(x) = (x - 2)

=> x = 2

By reminder theorem,

p(2)= 2^4 - 2×(2^3) + 3×(2^2) - 5×2 + 8

= 16 - 16 + 12 - 10 + 8

= 10

f(x)= (x+2)

=> x = -2

By reminder theorem,

p(x)= (-2)^4 - 2×(-2)^3 + 3×(-2)^2 - 5×(-2) + 8

= 16 + 16 + 12 + 10 + 8

= 62