if f(x) = X square + X + 1 then for what value of x ,f ( x )= f( 2 x -1)plz ans it fast
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xsqaure+x+1=f[2x-1]
f[2x-1]=[2x-1]square+[2x-1]+1
=4xsq.-2x+1
by using the formula,x=-b+_sq.root of bsq.-4ac\2a
=2+-i sq. root of 12\8
giti1:
the ans is wrong
Answered by
1
hey mate!
according to the question,
f(x) = f(2x - 1)
then,
2x-1 = 0
=> 2x = 0+1
=> x = 1/2
now,
f(x) = x² + x + 1
f(1/2) = (1/2)² + (1/2) + 1
= 1/4 + 1/2 +1/1
= (1+2+4)/4
= 7/4 ........Ans.
according to the question,
f(x) = f(2x - 1)
then,
2x-1 = 0
=> 2x = 0+1
=> x = 1/2
now,
f(x) = x² + x + 1
f(1/2) = (1/2)² + (1/2) + 1
= 1/4 + 1/2 +1/1
= (1+2+4)/4
= 7/4 ........Ans.
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