Question

If f(x)=x²+1, h=1 then 1 backward difference of Vf(x) in given by​

Answer 1

Answer:

Pomegranates (Punica granatum) are monoecious plants. Monoecious is a flowering term that means it has both male (pollen-forming) and female (ovary- and fruit-forming) reproductive organs on the same plant. ... The imperfect flowers on pomegranates are male only, so they produce pollen and then fall to the ground.

Step-by-step explanation:

Pomegranates (Punica granatum) are monoecious plants. Monoecious is a flowering term that means it has both male (pollen-forming) and female (ovary- and fruit-forming) reproductive organs on the same plant. ... The imperfect flowers on pomegranates are male only, so they produce pollen and then fall to the ground.

Answer 2

Answer:

The backward difference of the function is $\triangledown f(x)=2x-1$

Step-by-step explanation:

The correct question is-"If f(x)=x²+1, h=1 then 1 backward difference of $\triangledown f(x)$ is given by?" ​

The given function is $f(x)=x^{2}+1$ and scale of difference is given as $h=1$

The backward difference of the function is given by the relation as shown-

$\triangledown f(x)=f(x)-f(x-h)$

To find the backward difference we need to find the value of $f(x-h)$.It is found as shown below-

$f(x-h)=f(x-1)=(x-1)^{2}+1=x^{2} +1-2x+1\\=x^{2} -2x+2$

Now substituting this value in above relation of backward difference,we get

$\triangledown f(x)=f(x)-f(x-h)\\=(x^{2} +1)-(x^{2} -2x+2)=2x-1$

Therefore,the backward difference of the function is $\triangledown f(x)=2x-1$

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