If f(x)= √(x²-1), then f'(x) is * a) 1/[2x√(x²-1)] b) 1/[2√(x²-1)] c) 1/√(x²-1) d) x/√(x²-1)
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Answer:
y = √(x² - 1)
dy/dx = 1/2√(x² - 1) × 2x
[ power rule and chain rule]
=> x/√(x² - 1)
option d
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