Math, asked by AniketSingh2910, 9 months ago

If f(x)= √(x²-1), then f'(x) is * a) 1/[2x√(x²-1)] b) 1/[2√(x²-1)] c) 1/√(x²-1) d) x/√(x²-1)

Answers

Answered by biligiri
1

Answer:

y = √(x² - 1)

dy/dx = 1/2√(x² - 1) × 2x

[ power rule and chain rule]

=> x/√(x² - 1)

option d

Similar questions